Find roots of polynomial $$ p(x) = -3x^2+19 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{\sqrt{ 57 }}{ 3 }\\[1 em]x_2 &= - \frac{\sqrt{ 57 }}{ 3 } \end{aligned} $$Explanation
The solutions of $ -3x^2+19 = 0 $ are: $ x = - \dfrac{\sqrt{ 57 }}{ 3 } ~ \text{and} ~ x = \dfrac{\sqrt{ 57 }}{ 3 }$.
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