Find roots of polynomial $$ p(x) = -3x^2+18x+36 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 7.5826\\[1 em]x_2 &= -1.5826 \end{aligned} $$Explanation
The solutions of $ -3x^2+18x+36 = 0 $ are: $ x = 3-\sqrt{ 21 } ~ \text{and} ~ x = 3+\sqrt{ 21 }$.
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