Find roots of polynomial $$ p(x) = -3x^2-18x+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.2146\\[1 em]x_2 &= -6.2146 \end{aligned} $$Explanation
The solutions of $ -3x^2-18x+4 = 0 $ are: $ x = -3-\dfrac{\sqrt{ 93 }}{ 3 } ~ \text{and} ~ x = -3+\dfrac{\sqrt{ 93 }}{ 3 }$.
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