Find roots of polynomial $$ p(x) = -2x^2+8x-3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3.5811\\[1 em]x_2 &= 0.4189 \end{aligned} $$Explanation
The solutions of $ -2x^2+8x-3 = 0 $ are: $ x = 2-\dfrac{\sqrt{ 10 }}{ 2 } ~ \text{and} ~ x = 2+\dfrac{\sqrt{ 10 }}{ 2 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator