Find roots of polynomial $$ p(x) = -16x^2+64x+64 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4.8284\\[1 em]x_2 &= -0.8284 \end{aligned} $$Explanation
The solutions of $ -16x^2+64x+64 = 0 $ are: $ x = 2-2 \sqrt{ 2 } ~ \text{and} ~ x = 2+2 \sqrt{ 2 }$.
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