Find roots of polynomial $$ p(x) = -15x^2+4x-8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 2 }{ 15 }+\frac{ 2 \sqrt{ 29}}{ 15 }i\\[1 em]x_2 &= \frac{ 2 }{ 15 }-2 \frac{\sqrt{ 29 }}{ 15 }i \end{aligned} $$Explanation
The solutions of $ -15x^2+4x-8 = 0 $ are: $ x = \dfrac{ 2 }{ 15 }+\dfrac{ 2 \sqrt{ 29}}{ 15 }i ~ \text{and} ~ x = \dfrac{ 2 }{ 15 }-\dfrac{ 2 \sqrt{ 29}}{ 15 }i$.
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