Find roots of polynomial $$ p(x) = -12x^2+8x+3 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.9343\\[1 em]x_2 &= -0.2676 \end{aligned} $$Explanation
The solutions of $ -12x^2+8x+3 = 0 $ are: $ x = \dfrac{ 1 }{ 3 }-\dfrac{\sqrt{ 13 }}{ 6 } ~ \text{and} ~ x = \dfrac{ 1 }{ 3 }+\dfrac{\sqrt{ 13 }}{ 6 }$.
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