Find roots of polynomial $$ p(x) = -1000x^2+800+350 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{\sqrt{ 115 }}{ 10 }\\[1 em]x_2 &= - \frac{\sqrt{ 115 }}{ 10 } \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ -1000x^2+ \color{blue}{800} + \color{blue}{350} = -1000x^2+ \color{blue}{1150} $$Step 2:
The solutions of $ -1000x^2+1150 = 0 $ are: $ x = - \dfrac{\sqrt{ 115 }}{ 10 } ~ \text{and} ~ x = \dfrac{\sqrt{ 115 }}{ 10 }$.
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