Find roots of polynomial $$ p(x) = -\frac{1}{2500}t^2-1 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 50i\\[1 em]t_2 &= -50i \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 2500 } $.
$$ \begin{aligned} -\frac{1}{2500}t^2-1 & = 0 ~~~ / \cdot \color{blue}{ 2500 } \\[1 em] -t^2-2500 & = 0 \end{aligned} $$Step 2:
The solutions of $ -t^2-2500 = 0 $ are: $ t = 50 i ~ \text{and} ~ t = -50 i $.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator