Find roots of polynomial $$ p(x) = 14x^4+95x^2+144x $$

The roots of polynomial $ p(x) $ are:

$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= -1.2369\\[1 em]x_3 &= 0.6185+2.8166i\\[1 em]x_4 &= 0.6185-2.8166i \end{aligned} $$

Step 1:

Factor out $ \color{blue}{ x }$ from $ 14x^4+95x^2+144x $ and solve two separate equations:

$$ \begin{aligned} 14x^4+95x^2+144x & = 0\\[1 em] \color{blue}{ x }\cdot ( 14x^3+95x+144 ) & = 0 \\[1 em] \color{blue}{ x = 0} ~~ \text{or} ~~ 14x^3+95x+144 & = 0 \end{aligned} $$

One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.

Step 2:

Polynomial $ 14x^3+95x+144 $ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.

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