Sketch the graph of the polynomial function $$ p(x) = x^4-4x^3+8x^2-10x-4 $$

Tap the blue points to see coordinates.

STEP 1:Find the x-intercepts

To find the x-intercepts solve, the equation $ \color{blue}{ x^4-4x^3+8x^2-10x-4 = 0 } $

The solutions of this equation are:

$$ \begin{matrix}x_1 = -0.3102 & x_2 = 2.6248 \end{matrix} $$

(you can use the step-by-step polynomial equation solver to see a detailed explanation of how to solve the equation)

STEP 2:Find the y-intercepts

To find the y-intercepts, substitute $ x = 0 $ into $ \color{blue}{ p(x) = x^4-4x^3+8x^2-10x-4 } $, so:

$$ \text{Y inercept} = p(0) = -4 $$

STEP 3:Find the end behavior

The end behavior of a polynomial is the same as the end behavior of a leading term.

$$ \lim_{x \to -\infty} \left( x^4-4x^3+8x^2-10x-4 \right) = \lim_{x \to -\infty} x^4 = \color{blue}{ \infty } $$

The graph starts in the upper-left corner.

$$ \lim_{x \to \infty} \left( x^4-4x^3+8x^2-10x-4 \right) = \lim_{x \to \infty} x^4 = \color{blue}{ \infty } $$

The graph ends in the upper-right corner.

STEP 4:Find the turning points

To determine the turning point, we need to find the first derivative of $ p(x) $:

$$ p^{\prime} (x) = 4x^3-12x^2+16x-10 $$

The x coordinate of the turning point is located at the zeros of the first derivative

$$ p^{\prime} (x) = 0 $$ $$ \begin{matrix}x = 1.4239 \end{matrix} $$

(cleck here to see a explanation of how to solve the equation)

To find the y coordinate, substitute the above value into $ p(x) $

$$ \begin{aligned} \text{for } ~ x & = \color{blue}{ 1.4239 } \Rightarrow p\left(1.4239\right) = \color{orangered}{ -9.4561 }\end{aligned} $$

So the turning point is:

$$ \begin{matrix} \left( 1.4239, -9.4561 \right)\end{matrix} $$

STEP 5:Find the inflection points

The inflection points are located at zeroes of second derivative. The second derivative is $ p^{\prime \prime} (x) = 12x^2-24x+16 $.

Since above equation has no solutions we conclude that
polynomial has no inflection points.

Graphing Polynomials