Sketch the graph of the polynomial function $$ p(l) = 60+5l+2l^2 $$

Tap the blue points to see coordinates.

STEP 1:Find the x-intercepts

To find the x-intercepts solve, the equation $ \color{blue}{ 60+5l+2l^2 = 0 } $

Since above equation has no solutions we conclude that
polynomial has no x-intecepts.

(you can use the step-by-step polynomial equation solver to see a detailed explanation of how to solve the equation)

STEP 2:Find the y-intercepts

To find the y-intercepts, substitute $ l = 0 $ into $ \color{blue}{ p(l) = 60+5l+2l^2 } $, so:

$$ \text{Y inercept} = p(0) = 60 $$

STEP 3:Find the end behavior

The end behavior of a polynomial is the same as the end behavior of a leading term.

$$ \lim_{x \to -\infty} \left( 60+5l+2l^2 \right) = \lim_{x \to -\infty} 60 = \color{blue}{ \infty } $$

The graph starts in the upper-left corner.

$$ \lim_{x \to \infty} \left( 60+5l+2l^2 \right) = \lim_{x \to \infty} 60 = \color{blue}{ \infty } $$

The graph ends in the upper-right corner.

STEP 4:Find the turning points

To determine the turning point, we need to find the first derivative of $ p(l) $:

$$ p^{\prime} (x) = 4l+5 $$

The x coordinate of the turning point is located at the zeros of the first derivative

$$ p^{\prime} (l) = 0 $$ $$ \begin{matrix}l = -\dfrac{ 5 }{ 4 } \end{matrix} $$

(cleck here to see a explanation of how to solve the equation)

To find the y coordinate, substitute the above value into $ p(l) $

$$ \begin{aligned} \text{for } ~ l & = \color{blue}{ -\frac{ 5 }{ 4 } } \Rightarrow p\left(-\frac{ 5 }{ 4 }\right) = \color{orangered}{ \frac{ 455 }{ 8 } }\end{aligned} $$

So the turning point is:

$$ \begin{matrix} \left( -\dfrac{ 5 }{ 4 }, \dfrac{ 455 }{ 8 } \right)\end{matrix} $$

Graphing Polynomials