Tap the blue points to see coordinates.
STEP 1:Find the x-intercepts
To find the x-intercepts solve, the equation $ \color{blue}{ 2x^3-x^2-7x+6+x^6+x^5-2x^{11} = 0 } $
The solution of this equation is:
$$ \begin{matrix}x = 1 \end{matrix} $$(you can use the step-by-step polynomial equation solver to see a detailed explanation of how to solve the equation)
STEP 2:Find the y-intercepts
To find the y-intercepts, substitute $ x = 0 $ into $ \color{blue}{ p(x) = 2x^3-x^2-7x+6+x^6+x^5-2x^{11} } $, so:
$$ \text{Y inercept} = p(0) = 6 $$STEP 3:Find the end behavior
The end behavior of a polynomial is the same as the end behavior of a leading term.
$$ \lim_{x \to -\infty} \left( 2x^3-x^2-7x+6+x^6+x^5-2x^{11} \right) = \lim_{x \to -\infty} 2x^3 = \color{blue}{ -\infty } $$The graph starts in the lower-left corner.
$$ \lim_{x \to \infty} \left( 2x^3-x^2-7x+6+x^6+x^5-2x^{11} \right) = \lim_{x \to \infty} 2x^3 = \color{blue}{ \infty } $$The graph ends in the upper-right corner.
STEP 4:Find the turning points
To determine the turning points, we need to find the first derivative of $ p(x) $:
$$ p^{\prime} (x) = -22x^{10}+6x^5+5x^4+6x^2-2x-7 $$The x coordinate of the turning points are located at the zeros of the first derivative
$$ p^{\prime} (x) = 0 $$ $$ \begin{matrix} \end{matrix} $$(cleck here to see a explanation of how to solve the equation)
To find the y coordinates, substitute the above values into $ p(x) $
$$ $$So the turning points are:
$$ $$STEP 5:Find the inflection points
The inflection points are located at zeroes of second derivative. The second derivative is $ p^{\prime \prime} (x) = -220x^9+30x^4+20x^3+12x-2 $.
The zeros of second derivative are
$$ \begin{matrix}x_1 = 0.1585 & x_2 = -0.7098 & x_3 = 0.8027 \end{matrix} $$Substitute the x values into $ p(x) $ to get y coordinates
$$ \begin{aligned} \text{for } ~ x & = \color{blue}{ 0.1585 } \Rightarrow p\left(0.1585\right) = \color{orangered}{ 4.8737 }\\[1 em] \text{for } ~ x & = \color{blue}{ -0.7098 } \Rightarrow p\left(-0.7098\right) = \color{orangered}{ 9.7432 }\\[1 em] \text{for } ~ x & = \color{blue}{ 0.8027 } \Rightarrow p\left(0.8027\right) = \color{orangered}{ 1.1937 }\end{aligned} $$So the inflection points are:
$$ \begin{matrix} \left( 0.1585, 4.8737 \right) & \left( -0.7098, 9.7432 \right) & \left( 0.8027, 1.1937 \right)\end{matrix} $$