Sketch the graph of the polynomial function $$ p(x) = -x^4+2x^3+13x^2-14x-24 $$

Tap the blue points to see coordinates.

STEP 1:Find the x-intercepts

To find the x-intercepts solve, the equation $ \color{blue}{ -x^4+2x^3+13x^2-14x-24 = 0 } $

The solutions of this equation are:

$$ \begin{matrix}x_1 = 2 & x_2 = 4 & x_3 = -1 & x_4 = -3 \end{matrix} $$

(you can use the step-by-step polynomial equation solver to see a detailed explanation of how to solve the equation)

STEP 2:Find the y-intercepts

To find the y-intercepts, substitute $ x = 0 $ into $ \color{blue}{ p(x) = -x^4+2x^3+13x^2-14x-24 } $, so:

$$ \text{Y inercept} = p(0) = -24 $$

STEP 3:Find the end behavior

The end behavior of a polynomial is the same as the end behavior of a leading term.

$$ \lim_{x \to -\infty} \left( -x^4+2x^3+13x^2-14x-24 \right) = \lim_{x \to -\infty} -x^4 = \color{blue}{ -\infty } $$

The graph starts in the lower-left corner.

$$ \lim_{x \to \infty} \left( -x^4+2x^3+13x^2-14x-24 \right) = \lim_{x \to \infty} -x^4 = \color{blue}{ -\infty } $$

The graph ends in the lower-right corner.

STEP 4:Find the turning points

To determine the turning points, we need to find the first derivative of $ p(x) $:

$$ p^{\prime} (x) = -4x^3+6x^2+26x-14 $$

The x coordinate of the turning points are located at the zeros of the first derivative

$$ p^{\prime} (x) = 0 $$ $$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 } & x_2 = 3.1926 & x_3 = -2.1926 \end{matrix} $$

(cleck here to see a explanation of how to solve the equation)

To find the y coordinates, substitute the above values into $ p(x) $

$$ \begin{aligned} \text{for } ~ x & = \color{blue}{ \frac{ 1 }{ 2 } } \Rightarrow p\left(\frac{ 1 }{ 2 }\right) = \color{orangered}{ -\frac{ 441 }{ 16 } }\\[1 em] \text{for } ~ x & = \color{blue}{ 3.1926 } \Rightarrow p\left(3.1926\right) = \color{orangered}{ 25 }\\[1 em] \text{for } ~ x & = \color{blue}{ -2.1926 } \Rightarrow p\left(-2.1926\right) = \color{orangered}{ 25 }\end{aligned} $$

So the turning points are:

$$ \begin{matrix} \left( \dfrac{ 1 }{ 2 }, -\dfrac{ 441 }{ 16 } \right) & \left( 3.1926, 25 \right) & \left( -2.1926, 25 \right)\end{matrix} $$

STEP 5:Find the inflection points

The inflection points are located at zeroes of second derivative. The second derivative is $ p^{\prime \prime} (x) = -12x^2+12x+26 $.

The zeros of second derivative are

$$ \begin{matrix}x_1 = 2.0546 & x_2 = -1.0546 \end{matrix} $$

Substitute the x values into $ p(x) $ to get y coordinates

$$ \begin{aligned} \text{for } ~ x & = \color{blue}{ 2.0546 } \Rightarrow p\left(2.0546\right) = \color{orangered}{ 1.6389 }\\[1 em] \text{for } ~ x & = \color{blue}{ -1.0546 } \Rightarrow p\left(-1.0546\right) = \color{orangered}{ 1.6389 }\end{aligned} $$

So the inflection points are:

$$ \begin{matrix} \left( 2.0546, 1.6389 \right) & \left( -1.0546, 1.6389 \right)\end{matrix} $$

Graphing Polynomials