Find the polynomial having roots at $1$ and $- \frac{45}{8}$ .

Answer

The polynomial generated from the given zeros is: $P (x) = 8 x^{2} + 37 x - 45$

Explanation

Step 1: Turn the zeros into factors:

Zero	Factor
$1$	$x - 1$
$- \frac{45}{8}$	$8 x + 45$

Step 2: Multiply the factors together:

P (x) = (x - 1) \cdot (8 x + 45) = 8 x^{2} + 37 x - 45

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Find the polynomial having roots at 1 and −845​ .

The polynomial generated from the given zeros is: P(x)=8x2+37x−45

Find the polynomial having roots at $1$ and $- \frac{45}{8}$ .

The polynomial generated from the given zeros is: $P (x) = 8 x^{2} + 37 x - 45$