Find the polynomial having roots at $- \frac{1}{2}$ , $- \frac{1}{3}$ , $1$ and $2$ .

Answer

The polynomial generated from the given zeros is: $P (x) = 6 x^{4} - 13 x^{3} - 2 x^{2} + 7 x + 2$

Explanation

Step 1: Turn the zeros into factors:

Zero	Factor
$- \frac{1}{2}$	$2 x + 1$
$- \frac{1}{3}$	$3 x + 1$
$1$	$x - 1$
$2$	$x - 2$

Step 2: Multiply the factors together:

P (x) = (2 x + 1) \cdot (3 x + 1) \cdot (x - 1) \cdot (x - 2) = 6 x^{4} - 13 x^{3} - 2 x^{2} + 7 x + 2

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Find the polynomial having roots at −21​ , −31​ , 1 and 2 .

The polynomial generated from the given zeros is: P(x)=6x4−13x3−2x2+7x+2

Find the polynomial having roots at $- \frac{1}{2}$ , $- \frac{1}{3}$ , $1$ and $2$ .

The polynomial generated from the given zeros is: $P (x) = 6 x^{4} - 13 x^{3} - 2 x^{2} + 7 x + 2$