Factor polynomial $$ y^{6}-x^{4} $$
Answer
$$ y^{6}-x^{4} = (y^{3}+x^{2})(y^{3}-x^{2}) $$
Explanation
Rewrite $ y^6-x^4 $ as:
$$ \color{blue}{ y^6-x^4 = (y^3)^2 - (x^2)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = y^3 $ and $ II = x^2 $ , we have:
$$ y^6-x^4 = (y^3)^2 - (x^2)^2 = ( y^3-x^2 ) ( y^3+x^2 ) $$This page was created using
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