Factor polynomial $$ y^{6}-100 $$
Answer
$$ y^{6}-100 = ( y^{3}-10 )( y^{3}+10 ) $$
Explanation
Rewrite $ y^{6}-100 $ as:
$$ y^{6}-100 = (y^{3})^2 - (10)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = y^{3} $ and $ II = 10 $ , we have:
$$ y^{6}-100 = (y^{3})^2 - (10)^2 = ( y^{3}-10 ) ( y^{3}+10 ) $$This page was created using
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