Factor polynomial $$ y^{3}+5y^{2}-2y $$

$$ y^{3}+5y^{2}-2y = y( y^{2}+5y-2 ) $$

Step 1 :

After factoring out $ y $ we have:

$$ y^{3}+5y^{2}-2y = y ( y^{2}+5y-2 ) $$

Step 2 :

Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = 5 } ~ \text{ and } ~ \color{red}{ c = -2 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ 5 } $ and multiply to $ \color{red}{ -2 } $.

Step 3: Find out pairs of numbers with a product of $\color{red}{ c = -2 }$.

PRODUCT = -2
-1     2	1     -2

Step 4: Because none of these pairs will give us a sum of $ \color{blue}{ 5 }$, we conclude the polynomial cannot be factored.

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