Factor polynomial $$ y^{3}-3y^{2}+4y-12 $$
Answer
$$ y^{3}-3y^{2}+4y-12 = ( y^{2}+4 )( y-3 ) $$
Explanation
To factor $ y^{3}-3y^{2}+4y-12 $ we can use factoring by grouping:
Group $ \color{blue}{ x^{3} }$ with $ \color{blue}{ -3x^{2} }$ and $ \color{red}{ 4x }$ with $ \color{red}{ -12 }$ then factor each group.
$$ \begin{aligned} y^{3}-3y^{2}+4y-12 = ( \color{blue}{ x^{3}-3x^{2} } ) + ( \color{red}{ 4x-12 }) &= \\ &= \color{blue}{ x^{2}( x-3 )} + \color{red}{ 4( x-3 ) } = \\ &= (x^{2}+4)(x-3) \end{aligned} $$This page was created using
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