Factor polynomial $$ y^{3}-3y^{2}-6y+18 $$
Answer
$$ y^{3}-3y^{2}-6y+18 = ( y^{2}-6 )( y-3 ) $$
Explanation
To factor $ y^{3}-3y^{2}-6y+18 $ we can use factoring by grouping:
Group $ \color{blue}{ x^{3} }$ with $ \color{blue}{ -3x^{2} }$ and $ \color{red}{ -6x }$ with $ \color{red}{ 18 }$ then factor each group.
$$ \begin{aligned} y^{3}-3y^{2}-6y+18 = ( \color{blue}{ x^{3}-3x^{2} } ) + ( \color{red}{ -6x+18 }) &= \\ &= \color{blue}{ x^{2}( x-3 )} + \color{red}{ -6( x-3 ) } = \\ &= (x^{2}-6)(x-3) \end{aligned} $$This page was created using
Polynomial Factoring Calculator