Factor polynomial $$ y^{2}-16 $$
Answer
$$ y^{2}-16 = ( y-4 )( y+4 ) $$
Explanation
Rewrite $ y^{2}-16 $ as:
$$ y^{2}-16 = (y)^2 - (4)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = y $ and $ II = 4 $ , we have:
$$ y^{2}-16 = (y)^2 - (4)^2 = ( y-4 ) ( y+4 ) $$This page was created using
Polynomial Factoring Calculator