Factor polynomial $$ x^{6}+1 $$
Answer
$$ x^{6}+1 = ( x^{2}+1 )( x^{4}-x^{2}+1 ) $$
Explanation
To factor $ x^{6}+1 $ we can use sum of cubes formula:
$$ I^3 - II^3 = (I + II)(I^2 - I \cdot II + II^2) $$After putting $ I = x^{2} $ and $ II = 1 $ , we have:
$$ x^{6}+1 = ( x^{2}+1 ) ( x^{4}-x^{2}+1 ) $$This page was created using
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