Factor polynomial $$ x^{6}-y^{9} $$
Answer
$$ x^{6}-y^{9} = (x^{2}-y^{3})(x^{4}+x^{2}y^{3}+y^{6}) $$
Explanation
To factor $ x^{6}-y^{9} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = x^2 $ and $ II = y^3 $ , we have:
$$ x^{6}-y^{9} = ( x^{2}-y^{3} ) ( x^{4}+x^{2}y^{3}+y^{6} ) $$This page was created using
Polynomial Factoring Calculator