Factor polynomial $$ x^{6}-8y^{3} $$
Answer
$$ x^{6}-8y^{3} = (x^{2}-2y)(x^{4}+2x^{2}y+4y^{2}) $$
Explanation
To factor $ x^{6}-8y^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = x^2 $ and $ II = 2y $ , we have:
$$ x^{6}-8y^{3} = ( x^{2}-2y ) ( x^{4}+2x^{2}y+4y^{2} ) $$This page was created using
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