Rewrite $ x^{4}-25 $ as:
$$ x^{4}-25 = (x^{2})^2 - (5)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = x^{2} $ and $ II = 5 $ , we have:
$$ x^{4}-25 = (x^{2})^2 - (5)^2 = ( x^{2}-5 ) ( x^{2}+5 ) $$