Factor polynomial $$ x^{3}+x^{2}+4x+4 $$
Answer
$$ x^{3}+x^{2}+4x+4 = ( x^{2}+4 )( x+1 ) $$
Explanation
To factor $ x^{3}+x^{2}+4x+4 $ we can use factoring by grouping:
Group $ \color{blue}{ x^{3} }$ with $ \color{blue}{ x^{2} }$ and $ \color{red}{ 4x }$ with $ \color{red}{ 4 }$ then factor each group.
$$ \begin{aligned} x^{3}+x^{2}+4x+4 = ( \color{blue}{ x^{3}+x^{2} } ) + ( \color{red}{ 4x+4 }) &= \\ &= \color{blue}{ x^{2}( x+1 )} + \color{red}{ 4( x+1 ) } = \\ &= (x^{2}+4)(x+1) \end{aligned} $$This page was created using
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