Factor polynomial $$ x^{3}+5x^{2}+9x+45 $$
Answer
$$ x^{3}+5x^{2}+9x+45 = ( x^{2}+9 )( x+5 ) $$
Explanation
To factor $ x^{3}+5x^{2}+9x+45 $ we can use factoring by grouping:
Group $ \color{blue}{ x^{3} }$ with $ \color{blue}{ 5x^{2} }$ and $ \color{red}{ 9x }$ with $ \color{red}{ 45 }$ then factor each group.
$$ \begin{aligned} x^{3}+5x^{2}+9x+45 = ( \color{blue}{ x^{3}+5x^{2} } ) + ( \color{red}{ 9x+45 }) &= \\ &= \color{blue}{ x^{2}( x+5 )} + \color{red}{ 9( x+5 ) } = \\ &= (x^{2}+9)(x+5) \end{aligned} $$This page was created using
Polynomial Factoring Calculator