Factor polynomial $$ p^{3}x^{3}-y^{6} $$
Answer
$$ p^{3}x^{3}-y^{6} = (px-y^{2})(p^{2}x^{2}+pxy^{2}+y^{4}) $$
Explanation
To factor $ p^{3}x^{3}-y^{6} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = px $ and $ II = y^2 $ , we have:
$$ p^{3}x^{3}-y^{6} = ( px-y^{2} ) ( p^{2}x^{2}+pxy^{2}+y^{4} ) $$This page was created using
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