Factor polynomial $$ x^{2}y+10y+4x^{2}+40 $$

$$ x^{2}y+10y+4x^{2}+40 = (y+4)(x^{2}+10) $$

To factor $ x^2y+10y+4x^2+40 $ we can use factoring by grouping.

Group $ \color{blue}{ x^2y }$ with $ \color{blue}{ 10y }$ and $ \color{red}{ 4x^2 }$ with $ \color{red}{ 40 }$ then factor each group.

$$ \begin{aligned} x^2y+10y+4x^2+40 &= ( \color{blue}{ x^2y+10y } ) + ( \color{red}{ 4x^2+40 }) = \\ &= \color{blue}{ y( x^2+10 )} + \color{red}{ 4( x^2+10 ) } = \\ &= (y+4)(x^2+10) \end{aligned} $$

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