It seems that $ x^{2}+3x-36 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 3 } ~ \text{ and } ~ \color{red}{ c = -36 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 3 } $ and multiply to $ \color{red}{ -36 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -36 }$.
PRODUCT = -36 | |
-1 36 | 1 -36 |
-2 18 | 2 -18 |
-3 12 | 3 -12 |
-4 9 | 4 -9 |
-6 6 | 6 -6 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ 3 }$, we conclude the polynomial cannot be factored.