It seems that $ x^{2}+18x+90 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 18 } ~ \text{ and } ~ \color{red}{ c = 90 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 18 } $ and multiply to $ \color{red}{ 90 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 90 }$.
PRODUCT = 90 | |
1 90 | -1 -90 |
2 45 | -2 -45 |
3 30 | -3 -30 |
5 18 | -5 -18 |
6 15 | -6 -15 |
9 10 | -9 -10 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ 18 }$, we conclude the polynomial cannot be factored.