It seems that $ x^{2}+18x+54 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 18 } ~ \text{ and } ~ \color{red}{ c = 54 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 18 } $ and multiply to $ \color{red}{ 54 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 54 }$.
PRODUCT = 54 | |
1 54 | -1 -54 |
2 27 | -2 -27 |
3 18 | -3 -18 |
6 9 | -6 -9 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ 18 }$, we conclude the polynomial cannot be factored.