It seems that $ x^{2}-10x+60 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = -10 } ~ \text{ and } ~ \color{red}{ c = 60 }$$Now we must discover two numbers that sum up to $ \color{blue}{ -10 } $ and multiply to $ \color{red}{ 60 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 60 }$.
PRODUCT = 60 | |
1 60 | -1 -60 |
2 30 | -2 -30 |
3 20 | -3 -20 |
4 15 | -4 -15 |
5 12 | -5 -12 |
6 10 | -6 -10 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ -10 }$, we conclude the polynomial cannot be factored.