Factor polynomial $$ r^{2}-6r-40 $$

$$ r^{2}-6r-40 = ( r+4 )( r-10 ) $$

Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = -6 } ~ \text{ and } ~ \color{red}{ c = -40 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ -6 } $ and multiply to $ \color{red}{ -40 } $.

Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -40 }$.

PRODUCT = -40
-1     40	1     -40
-2     20	2     -20
-4     10	4     -10
-5     8	5     -8

Step 3: Find out which pair sums up to $\color{blue}{ b = -6 }$

PRODUCT = -40 and SUM = -6
-1     40	1     -40
-2     20	2     -20
-4     10	4     -10
-5     8	5     -8

Step 4: Put 4 and -10 into placeholders to get factored form.

$$ \begin{aligned} r^{2}-6r-40 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ r^{2}-6r-40 & = (x + 4)(x -10) \end{aligned} $$

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