It seems that $ p^{2}-13p+15 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = -13 } ~ \text{ and } ~ \color{red}{ c = 15 }$$Now we must discover two numbers that sum up to $ \color{blue}{ -13 } $ and multiply to $ \color{red}{ 15 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 15 }$.
PRODUCT = 15 | |
1 15 | -1 -15 |
3 5 | -3 -5 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ -13 }$, we conclude the polynomial cannot be factored.