It seems that $ n^{2}-7n-7 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = -7 } ~ \text{ and } ~ \color{red}{ c = -7 }$$Now we must discover two numbers that sum up to $ \color{blue}{ -7 } $ and multiply to $ \color{red}{ -7 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -7 }$.
PRODUCT = -7 | |
-1 7 | 1 -7 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ -7 }$, we conclude the polynomial cannot be factored.