Factor polynomial $$ m^{3}+64n^{3} $$
Answer
$$ m^{3}+64n^{3} = (m+4n)(m^{2}-4mn+16n^{2}) $$
Explanation
To factor $ m^{3}+64n^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = m $ and $ II = 4n $ , we have:
$$ m^{3}+64n^{3} = ( m+4n ) ( m^{2}-4mn+16n^{2} ) $$This page was created using
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