Factor polynomial $$ m^{2}-64n^{2} $$
Answer
$$ m^{2}-64n^{2} = (m+8n)(m-8n) $$
Explanation
Rewrite $ m^2-64n^2 $ as:
$$ \color{blue}{ m^2-64n^2 = (m)^2 - (8n)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = m $ and $ II = 8n $ , we have:
$$ m^2-64n^2 = (m)^2 - (8n)^2 = ( m-8n ) ( m+8n ) $$This page was created using
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