Factor polynomial $$ m^{2}-11m+18 $$

$$ m^{2}-11m+18 = ( m-2 )( m-9 ) $$

Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = -11 } ~ \text{ and } ~ \color{red}{ c = 18 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ -11 } $ and multiply to $ \color{red}{ 18 } $.

Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 18 }$.

PRODUCT = 18
1     18	-1     -18
2     9	-2     -9
3     6	-3     -6

Step 3: Find out which pair sums up to $\color{blue}{ b = -11 }$

PRODUCT = 18 and SUM = -11
1     18	-1     -18
2     9	-2     -9
3     6	-3     -6

Step 4: Put -2 and -9 into placeholders to get factored form.

$$ \begin{aligned} m^{2}-11m+18 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ m^{2}-11m+18 & = (x -2)(x -9) \end{aligned} $$

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