Factor polynomial $$ h^{4}-256 $$
Answer
$$ h^{4}-256 = ( h-4 )( h+4 )( h^{2}+16 ) $$
Explanation
Step 1 :
Rewrite $ h^{4}-256 $ as:
$$ h^{4}-256 = (h^{2})^2 - (16)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = h^{2} $ and $ II = 16 $ , we have:
$$ h^{4}-256 = (h^{2})^2 - (16)^2 = ( h^{2}-16 ) ( h^{2}+16 ) $$Step 2 :
Rewrite $ h^{2}-16 $ as:
$$ h^{2}-16 = (h)^2 - (4)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = h $ and $ II = 4 $ , we have:
$$ h^{2}-16 = (h)^2 - (4)^2 = ( h-4 ) ( h+4 ) $$This page was created using
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