Factor polynomial $$ g^{2}+3g-40 $$

$$ g^{2}+3g-40 = ( g-5 )( g+8 ) $$

Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = 3 } ~ \text{ and } ~ \color{red}{ c = -40 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ 3 } $ and multiply to $ \color{red}{ -40 } $.

Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -40 }$.

PRODUCT = -40
-1     40	1     -40
-2     20	2     -20
-4     10	4     -10
-5     8	5     -8

Step 3: Find out which pair sums up to $\color{blue}{ b = 3 }$

PRODUCT = -40 and SUM = 3
-1     40	1     -40
-2     20	2     -20
-4     10	4     -10
-5     8	5     -8

Step 4: Put -5 and 8 into placeholders to get factored form.

$$ \begin{aligned} g^{2}+3g-40 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ g^{2}+3g-40 & = (x -5)(x + 8) \end{aligned} $$

Polynomial Factoring Calculator