Factor polynomial $$ f^{6}-g^{3} $$
Answer
$$ f^{6}-g^{3} = (f^{2}-g)(f^{4}+f^{2}g+g^{2}) $$
Explanation
To factor $ f^{6}-g^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = f^2 $ and $ II = g $ , we have:
$$ f^{6}-g^{3} = ( f^{2}-g ) ( f^{4}+f^{2}g+g^{2} ) $$This page was created using
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