Factor polynomial $$ b^{2}x^{2}-4b^{2}x-45b^{2} $$
Answer
$$ b^{2}x^{2}-4b^{2}x-45b^{2} = b^{2}(x+5)(x-9) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ b^2 } $:
$$ b^2x^2-4b^2x-45b^2 = b^2 ( x^2-4x-45 ) $$Step 2 :
$$ x^{2}-4x-45 = ( x + 5 )( x - 9 ) $$Click here to generate an explanation on how to factor $ x^{2}-4x-45 $.
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