Factor polynomial $$ b^{2}-16 $$
Answer
$$ b^{2}-16 = ( b-4 )( b+4 ) $$
Explanation
Rewrite $ b^{2}-16 $ as:
$$ b^{2}-16 = (b)^2 - (4)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = b $ and $ II = 4 $ , we have:
$$ b^{2}-16 = (b)^2 - (4)^2 = ( b-4 ) ( b+4 ) $$This page was created using
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