Factor polynomial $$ a^{6}b^{3}-1 $$
Answer
$$ a^{6}b^{3}-1 = (a^{2}b-1)(a^{4}b^{2}+a^{2}b+1) $$
Explanation
To factor $ a^{6}b^{3}-1 $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = a^2b $ and $ II = 1 $ , we have:
$$ a^{6}b^{3}-1 = ( a^{2}b-1 ) ( a^{4}b^{2}+a^{2}b+1 ) $$This page was created using
Polynomial Factoring Calculator