Factor polynomial $$ a^{2}+14ab+49b^{2} $$
Answer
$$ a^{2}+14ab+49b^{2} = (a+7b)(a+7b) $$
Explanation
Note that the polynomial $ a^2+14ab+49b^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 + 2AB + B^2 = (A + B)^2 $$In this example we have $ \color{blue}{ A = a } $ and $ \color{red}{ B = 7b } $ so,
$$ a^2+14ab+49b^2 = ( \color{blue}{ a } + \color{red}{ 7b } )^2 $$This page was created using
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