Factor polynomial $$ 9y^{4}-4 $$
Answer
$$ 9y^{4}-4 = ( 3y^{2}-2 )( 3y^{2}+2 ) $$
Explanation
Rewrite $ 9y^{4}-4 $ as:
$$ 9y^{4}-4 = (3y^{2})^2 - (2)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3y^{2} $ and $ II = 2 $ , we have:
$$ 9y^{4}-4 = (3y^{2})^2 - (2)^2 = ( 3y^{2}-2 ) ( 3y^{2}+2 ) $$This page was created using
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