It seems that $ 9x^{2}-84x+136 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 9 }$ by the constant term $\color{blue}{c = 136} $.
$$ a \cdot c = 1224 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 1224 $ and add to $ b = -84 $.
Step 4: All pairs of numbers with a product of $ 1224 $ are:
PRODUCT = 1224 | |
1 1224 | -1 -1224 |
2 612 | -2 -612 |
3 408 | -3 -408 |
4 306 | -4 -306 |
6 204 | -6 -204 |
8 153 | -8 -153 |
9 136 | -9 -136 |
12 102 | -12 -102 |
17 72 | -17 -72 |
18 68 | -18 -68 |
24 51 | -24 -51 |
34 36 | -34 -36 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -84 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -84 }$, we conclude the polynomial cannot be factored.