Factor polynomial $$ 10v^{3}-40v^{2}+9v-36 $$
Answer
$$ 10v^{3}-40v^{2}+9v-36 = ( 10v^{2}+9 )( v-4 ) $$
Explanation
To factor $ 10v^{3}-40v^{2}+9v-36 $ we can use factoring by grouping:
Group $ \color{blue}{ 10x^{3} }$ with $ \color{blue}{ -40x^{2} }$ and $ \color{red}{ 9x }$ with $ \color{red}{ -36 }$ then factor each group.
$$ \begin{aligned} 10v^{3}-40v^{2}+9v-36 = ( \color{blue}{ 10x^{3}-40x^{2} } ) + ( \color{red}{ 9x-36 }) &= \\ &= \color{blue}{ 10x^{2}( x-4 )} + \color{red}{ 9( x-4 ) } = \\ &= (10x^{2}+9)(x-4) \end{aligned} $$This page was created using
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